A can do a piece of work in 32 days

One day work of A and B = $\frac{1}{32} +\frac{1}{48}$
8 day work of A and B = $ 8(\frac{3+2}{96}) $
= $\frac{5}{12}$
Remaining work = $ 1- \frac{5}{12} = \frac{12 - 5}{12} = \frac{7}{12}$
60% of $\frac{7}{12} =\frac{60\times 7}{12\times 100} = \frac{7}{12} $
$ \frac{1}{48} $ work done by 'B' in 1 day
$\frac{7}{80} $ work will be done by B in = $48\times \frac{7}{20}$
= $ \frac{84}{5} = 16\frac{4}{5}$