A shopkeeper professes to sell his goods at a 55%
A shopkeeper professes to sell his goods at a 55% loss but uses a false balance and gains 75%. The actual weight (rounded off to one decimal place) he uses for 1 kg is:
एक दुकानदार अपने माल को 55% हानि पर बेचने का दावा करता है, लेकिन वह सदोष तुला का उपयोग करके 75% लाभ अर्जित करता है। 1 किलोग्राम के स्थान पर वह वास्तव में कितने किलोग्राम वजन (दशमलव के एक स्थान तक पूर्णांकित) का उपयोग करता है?
Detailed Solution & Logic
257 .1 gm
Let the cost price of 1 kg of goods be 100 units.
He claims a 55% loss, so selling price of “1 kg”:
$SP = 45$
But actually he earns 75% profit.
So the actual cost of the quantity he gives is:
$45 = 175%$ of CP
$CP=\frac{45\times100}{175}$
$CP=25.714...$
This means the actual quantity given costs only 25.714 units, while 1 kg costs 100 units.
Hence actual weight:
$\frac{25.714}{100}\times1000$
$=257.14\text{ gm}$
Rounded to one decimal place:
$257.1\text{ gm}$
Final Answer: 257.1 gm
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