A can do a piece of work in 32 days
A can do a piece of work in 32 days and B in 48 days. They work together for 8 days and then A goes away. In how much time (in days) will B finish the 60% of the remaining work?
A किसी कार्य को 32 दिनों में और B उसी कार्य को 48 दिनों मे पूरा कर सकता है। वे 8 दिनों तक एक साथ कार्य करते हैं और फिर A कार्य करना छोड़ देता है। शेष कार्य का 60% भाग B कितने समय (दिन में) पूरा करेगा?
Detailed Solution & Logic
Correct Answer:
\(16\frac{4}{5}\)
One day work of A and B = $\frac{1}{32} +\frac{1}{48}$
8 day work of A and B = $ 8(\frac{3+2}{96}) $
= $\frac{5}{12}$
Remaining work = $ 1- \frac{5}{12} = \frac{12 - 5}{12} = \frac{7}{12}$
60% of $\frac{7}{12} =\frac{60\times 7}{12\times 100} = \frac{7}{12} $
$ \frac{1}{48} $ work done by 'B' in 1 day
$\frac{7}{80} $ work will be done by B in = $48\times \frac{7}{20}$
= $ \frac{84}{5} = 16\frac{4}{5}$
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