A cylindrical tank of height 10 m
A cylindrical tank of height 10 m and radius 5 m has a small circular cut of 0.5 m radius on its top surface. What would be the total surface area of the tank?
यहां, हमें एक बेलनाकार टैंक का कुल सतही क्षेत्रफल निकालना है, जिसका ऊंचाई (height) 10 मीटर और त्रिज्या (radius) 5 मीटर है, और इसके शीर्ष पर 0.5 मीटर त्रिज्या वाला एक छोटा गोलाकार कट है।
Detailed Solution & Logic
Correct Answer:
\(\frac{599\pi }{4}\:m^2\)
r = 5,m,\ h = 10,m,\ r1 = 0.5,m
Curved surface area of tank = $ 2\pi r h = 2\pi(5)(10) = 100\pi $
Top surface with cut = $ \pi(r^2 - r1^2) = \pi(25 - 0.25) = 24.75\pi $
Bottom surface = $ \pi r^2 = 25\pi $
Total surface area = $ 100\pi + 24.75\pi + 25\pi = 149.75\pi\ \text{m}^2 $
$ \frac{599\pi}{4}\ \text{m}^2 $
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