A shopkeeper has one spherical laddoo of radius 7 cm.

Volume of a sphere $ V=\frac{4}{3}\pi r^3 $
Radius of big laddoo $ r_1=7\text{ cm} $
Radius of small laddoo $ r_2=3.5\text{ cm} $
Volume of big laddoo =$ \frac{4}{3}\pi (7)^3 $
Volume of one small laddoo $ =\frac{4}{3}\pi (3.5)^3 $
Number of small laddoos=$ \dfrac{\frac{4}{3}\pi (7)^3}{\frac{4}{3}\pi (3.5)^3} $
$ =\left(\dfrac{7}{3.5}\right)^3 $
$ =(2)^3 $
=8
Answer = {8}