“A trader invests ₹50,000 at an annual compound interest rate of 6%. Find half of the compound interest he will receive after 3 years.”

Given: P = ₹50,000, ; R = 6%, ; T = 3 years
Compound Interest formula: A = P 1 +$ \frac{R}{100})^T$ CI = A - P
A = 50000 (1 + \frac{6}{100})^3 = 50000 (1.06)^3 $
$ (1.06)^3 = 1.06 \times 1.06 \times 1.06 = 1.191016 $
A $50000 \times 1.191016 = 59550.8 $
CI = A - P = 59550.8 - 50000 = 9550.8 $
Half of CI = $ \frac{9550.8}{2} $= 4775.4
Answer = ₹4,775.4