A train starts from rest and reaches a velocity of 36 km/hr in 3 minutes with uniform acceleration.

Given / ज्ञात तथ्य:

• Initial velocity v = 0

• Final velocity v =36km/hr

• Time t = 3 minutes = 180 s
  
  Step 1: Velocity को m/s में बदलें

$v = 36 \times \frac{1000}{3600} = 10 \text{ m/s}$

Step 2: Distance का formula (uniform acceleration के लिए)

$s = ut + \frac{1}{2} a t^2$

चूंकि $u = 0$, इसलिए

$s = \frac{1}{2} a t^2$

Step 3: Acceleration $a$ निकालें

$v = u + at \implies 10 = 0 + a \cdot 180 \implies a = \frac{10}{180} = \frac{1}{18} \text{ m/s²}$

Step 4: Distance $s$ निकालें

$s = \frac{1}{2} \cdot \frac{1}{18} \cdot (180)^2 = \frac{1}{36} \cdot 32400 = 900 \text{ m}$

Answer / उत्तर:

$s = 900 \text{ meters}$ ✅