A wire with resistance R is cut into seven equal parts.
A wire with resistance R is cut into seven equal parts. These parts are then connected in parallel. If the equivalent resistance of this new combination is R′, what is the value of the ratio R / R′?
प्रतिरोध R वाले एक तार को सात बराबर भागों में काटा जाता है। फिर इन भागों को समानांतर क्रम में जोड़ा जाता है। यदि इस नए संयोजन का तुल्य प्रतिरोध R′ है, तो R / R′ का मान कितना होगा?
Detailed Solution & Logic
49
एक तार का प्रतिरोध $R$ है। इसे 7 बराबर हिस्सों में काटा गया।
तो प्रत्येक हिस्से का प्रतिरोध होगा:
$R_{\text{part}} = \frac{R}{7}$
अब इन 7 हिस्सों को समानांतर में जोड़ा गया। समानांतर में $n$ बराबर प्रतिरोधों का तुल्य प्रतिरोध:
$\frac{1}{R'} = n \cdot \frac{1}{R_{\text{part}}}$
यहाँ $n = 7$ और $R_{\text{part}} = \frac{R}{7}$, इसलिए:
$\frac{1}{R'} = 7 \cdot \frac{7}{R} = \frac{49}{R}$
$\Rightarrow R' = \frac{R}{49}$
तो अनुपात:
$\frac{R}{R'} = \frac{R}{R/49} = 49$
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