A’s salary is 40% more than B’s. If B’s salary increases by 20% and A’s increases by x%, then A’s new salary becomes 25% more than B ‘s new salary. What is the value of x?

Solution

Let B’s salary = 100

A’s salary = 40% more than B ⇒ $140$

After increase:
B’s new salary = $100 + 20% = 120$

A’s new salary = $140 + x% = 140 \left(1 + \frac{x}{100}\right)$

Given: A’s new salary is 25% more than B’s new salary
So,
$A = 1.25 \times 120 = 150$

Now solve:
$140 \left(1 + \frac{x}{100}\right) = 150$

$1 + \frac{x}{100} = \frac{150}{140} = \frac{15}{14}$

$\frac{x}{100} = \frac{15}{14} - 1 = \frac{1}{14}$

$x = \frac{100}{14} \approx 7.14%$

Final Answer:

👉 7.14%