Based on the alphabetical order,

We are given:

VZC, KPS, GLO, NSV

We are to find the odd one out, based on alphabetical order logic (not vowels/consonants or position in cluster).

Step 1: Convert letters to their positions in the alphabet

Step 2: Find the pattern in differences

We check difference between consecutive letters in each cluster:

1. VZC → V→Z = +4, Z→C = +3 (wrap around 26→1)

   • V(22) → Z(26) = +4 ✅

   • Z(26) → C(3) = +3 ✅

2. KPS → K→P = +5, P→S = +3

   • K(11) → P(16) = +5 ✅

   • P(16) → S(19) = +3 ✅

3. GLO → G→L = +5, L→O = +3

   • G(7) → L(12) = +5 ✅

   • L(12) → O(15) = +3 ✅

4. NSV → N→S = +5, S→V = +3

   • N(14) → S(19) = +5 ✅

   • S(19) → V(22) = +3 ✅

Step 3: Identify the odd one out

• KPS, GLO, NSV → differences: +5, +3 ✅ (pattern consistent)

• VZC → differences: +4, +3 ❌ (does not follow +5, +3 pattern)

Answer:

VZC is the odd one out.