Based on the alphabetical order,
Based on the alphabetical order, three of the following four are alike in a certain way and thus form a group. Which is the one that does not belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their position in the letter cluster)
अंग्रेज़ी वर्णमाला क्रम के आधार पर, निम्नलिखित चार अक्षर‑समूहों में से तीन किसी निश्चित तरीके से एक समान हैं और इस प्रकार वे एक समूह बनाते हैं। कौन‑सा अक्षर‑समूह उस समूह से संबंधित नहीं है? (नोट: असंगत अक्षर‑समूह व्यंजनों/स्वरों की संख्या या उनकी स्थिति पर आधारित नहीं है।)
Detailed Solution & Logic
HMP
DHK, HMP, YCF, VZC → which one does not belong?
The hint says: “not based on consonants/vowels or position in the cluster.” So it’s likely based on alphabetical order pattern.
D H K H M P Y C F V Z C
4 8 11 8 13 16 25 3 6 22 26 3
tep 2: Check differences between consecutive letters
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DHK → 4, 8, 11
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H − D = 8 − 4 = 4
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K − H = 11 − 8 = 3
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HMP → 8, 13, 16
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M − H = 13 − 8 = 5
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P − M = 16 − 13 = 3
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YCF → 25, 3, 6 → since letters wrap around Z → A (mod 26)
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C − Y = 3 − 25 = -22 → +26 = 4
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F − C = 6 − 3 = 3
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VZC → 22, 26, 3 → wrap around
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Z − V = 26 − 22 = 4
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C − Z = 3 − 26 = -23 → +26 = 3
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Step 3: Observe the pattern
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DHK: +4, +3
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HMP: +5, +3
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YCF: +4, +3
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VZC: +4, +3
✅ All except HMP have differences +4 then +3.
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HMP has +5 then +3 → breaks the pattern.
Step 4: Odd one out
HMP
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