Find the diameter of a spherical ball whose volume is  38.808 cm \(^3\).(Use\( \pi = \frac{22}{7}\))

Given:
Volume of sphere = 38.808 cm³
Formula: Volume of sphere = $\frac{4}{3}\pi r^3$

Step 1: Substitute values

$38.808 = \frac{4}{3} \times \frac{22}{7} \times r^3$

Step 2: Solve for $r^3$

$\frac{4}{3} \times \frac{22}{7} = \frac{88}{21}$

So,
$38.808 = \frac{88}{21} r^3$

$r^3 = \frac{38.808 \times 21}{88}$

$r^3 = \frac{814.968}{88} = 9.261$

Step 3: Find radius

$r = \sqrt[3]{9.261} \approx 2.1$ cm

Step 4: Find diameter

Diameter = $2r = 2 \times 2.1 = 4.2$ cm

Final Answer: 4.2 cm