Find the greatest common divisor of 90, 1020, and 2340.

Prime factorization
90 = \(2\times 3^2 \times 5\)
1020 = \(2^2 \times 3 \times 17\)
2340 = \(2^2 \times 3 \times 5 \times 13\)
Take common prime factors with smallest powers
common factors: \(2^1, 3^1, 5^1\)
Multiply common factors to get GCD
GCD = \(2\times 3 \times 5 = 30\)
Answer = 30