Find the value/मान ज्ञात करेंः\(9^3 – 9^2 +(\frac{40}{2})^2 – 5 +  8 \times 5 \)= _________

$9^3 = 729$

$9^2 = 81$

$\frac{40}{2} = 20$

$20^2 = 400$

$8 \times 5 = 40$

Now substitute:

$729 - 81 + 400 - 5 + 40$

$= 648 + 400 - 5 + 40$

$= 1048 - 5 + 40$

$= 1043 + 40$

$= 1083$

$\therefore$ Correct Answer: 1083