Find the value of

$[(42 \div 7)\times{\frac{42}{3}+\frac{19}{4}\times (8 - 4 )}]$
$= [6 \times {14 + \frac{19}{4}\times 4}]$
$= [6 \times (14 + 19)]$
$= 6 \times 33$
Answer =198