If an angle is $10^\circ$ more than twice its complemen... - Trigonometry MCQ Solution

If an angle is $10^\circ$ more than twice its complement, what is the angle?

If an angle is $10^\circ$ more than twice its complement, what is the angle?
अगर कोई कोण अपने पूरक कोण के दौगुने से $10^\circ$ अधिक है, तो वह कोण क्या हैं?

$50^\circ$ $55^\circ$ $63.33^\circ$ $65^\circ$

Detailed Solution & Logic

Correct Answer:

$63.33^\circ$

$ x=2(90-x)+10 $
$ x=180-2x+10 $
$ x=190-2x $
$ 3x=190 $
$ x=\dfrac{190}{3}^\circ $

If an angle is \(10^\circ\) more than twice its complement, what is the angle?

Detailed Solution & Logic

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If an angle is \(10^\circ\) more than twice its complement, what is the angle?

Detailed Solution & Logic

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