If cot $\theta = \frac{14}{3}$, then what is the value of cos $ \theta$ ? ($0^\circ < \theta < 90^\circ )$

$cot \theta = \frac{14}{3}$

$cot \theta = \frac{\text{Adjacent}}{\text{Opposite}}$

So,
Adjacent = 14, Opposite = 3

Hypotenuse $= \sqrt{14^2 + 3^2} = \sqrt{196 + 9} = \sqrt{205}$

Now,
$\cos \theta = \frac{\text{Adjacent}}{\text{Hypotenuse}} = \frac{14}{\sqrt{205}}$

Final Answer: $\frac{14}{\sqrt{205}}$