If in triangle ABC, DE || BC and AD/DB = \(\frac{1}{2}\), and AE = 5 cm, then EC is:
If in triangle ABC, DE || BC and AD/DB = \(\frac{1}{2}\), and AE = 5 cm, then EC is:
यदि त्रिभुज ABC में, DE || BC और AD/DB = \(\frac{1}{2}\), और AE = 5 सेमी, तो EC हैः
Detailed Solution & Logic
Correct Answer:
10 cm / सेमी
By the Basic Proportionality Theorem (Thales’ theorem):
$\frac{AD}{DB}=\frac{AE}{EC} $
Given:
$ \frac{AE}{EC} =\frac{1}{2}, $ and AE=5 cm
$ \frac{5}{EC}=\frac{1}{2} $
EC=10 cm
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