If the eight-digit number 59044p22 is divisible by 6, then the maximum value of p is:

Number: 59044p22

Divisible by 6 ⇒ divisible by 2 and 3

• Last digit is 2 ⇒ divisible by 2

Now sum of digits:
5 + 9 + 0 + 4 + 4 + p + 2 + 2 = 26 + p

For divisibility by 3:
26 + p must be divisible by 3

Check p values:

• p = 1 → 27
• p = 4 → 30
• p = 7 → 33

Maximum value of p = 7

Answer: 7