In a circle of radius 10cm, a chord of length 16 cm is drawn. Find the distance from the center of the circle to the chord.

Given:
Radius $r = 10$ cm
Chord length $AB = 16$ cm

Let the distance from the center to the chord be $d$. Draw a perpendicular from the center $O$ to the chord; it bisects the chord.

Half of the chord = $8$ cm

Using Pythagoras theorem in right triangle formed by radius, half chord, and perpendicular distance:

$d^2 + 8^2 = 10^2$

$d^2 + 64 = 100$

$d^2 = 36$

d = 6 cm

✅ Distance from center to chord = 6 cm