M, N, O, X, Y and Z are seated around a circular table facing the centre. O is the immediate neighbour of Y. Z sits second to the right of O. X is the immediate neighbour of both M and N. M is not the immediate neighbour of O. Who sits immediate left of Y?

Given:

1. O is immediate neighbour of Y
2. Z is second to the right of O
3. X is immediate neighbour of both M and N
4. M is not immediate neighbour of O

Step 1: Fix O and Y

Since O is neighbour of Y → place them together.

👉 Assume order: O – Y

Step 2: Place Z

Z is second to the right of O (clockwise):

👉 O → (1st) → (2nd) = Z

Step 3: Place X, M, N

• X is between M and N → M – X – N (or N – X – M)
• Also, M cannot sit next to O

Step 4: Arrange all satisfying conditions

Final valid arrangement (clockwise):
👉 O – Y – M – X – N – Z

✔ Check:

• O next to Y ✔
• Z is 2nd right of O ✔
• X between M and N ✔
• M not next to O ✔

❓ Who is immediate left of Y?

Left of Y = anticlockwise from Y

👉 That is O

Final Answer:

👉 O