Sharad invested two equal amounts for 6 years and 3 years

Let each invested amount be $ x $
SI for first investment (6 years at 7%): SI1 =$ \frac{x \times 7 \times 6}{100} = \frac{42x}{100} $
SI for second investment (3 years at 9%): SI2 = $\frac{x \times 9 \times 3}{100} = \frac{27x}{100} $
Total SI: SI1 + SI2 = $ \frac{42x + 27x}{100} = \frac{69x}{100} = 1587 $
$ 69x = 158700 $
$ x = 2300 $
Total invested by Sharad = $ 2300 \times 2 = 4600 $
Answer = 4600