The distance between points A and B is 966 km.

Problem: Distance between A and B is 966 km. Kamlesh goes from A to B at 52 km/hr and returns at 118 km/hr. Find the average speed.

Step 1: Use the formula for average speed in a round trip

If the distance is the same in both directions, average speed = $ \frac{2 \cdot v_1 \cdot v_2}{v_1 + v_2} $

Here, $v_1 = 52$ km/hr, $v_2 = 118$ km/hr.

Step 2: Substitute values

Average speed = $ \frac{2 \cdot 52 \cdot 118}{52 + 118} $

Numerator: $ 2 \cdot 52 \cdot 118 = 12272 $

Denominator: $ 52 + 118 = 170 $

Divide: $ \frac{12272}{170} \approx 72.19 $ km/hr

Answer: $72.19$ km/hr