The least multiple of 11, which leaves a remainder of 8,

LCM (5,3,18,20)=180
N-8=180k
N=180k+8
$ 180k+8 \equiv 0 \pmod{11} $
$ 180 \equiv 4 \pmod{11} $
$ 4k+8 \equiv 0 \pmod{11} $
$ 4k \equiv 3 \pmod{11} $
k=9
$ N=180\times9+8=1628 $
Answer = 1628