What is the smallest number that should be added to 3857 so that the sum is completely divisible by 5, 6, 4, and 3?

To make the number divisible by 5, 6, 4, and 3, we first find their LCM (Least Common Multiple).

LCM of 5, 6, 4, and 3 = 60

Now we need to make 3857 divisible by 60.

Step 1: Find remainder when 3857 ÷ 60

3857 ÷ 60 = 64 remainder 17

Step 2: Find number to add

To reach the next multiple of 60:

Required number = 60 − 17 = 43

Final Answer: 43
Correct option: 43