What is the smallest perfect square divisible by each of 6, 12 and 18?

First find LCM of $6, 12, 18$

$6 = 2 \times 3$

$12 = 2^2 \times 3$

$18 = 2 \times 3^2$

LCM $= 2^2 \times 3^2$

$= 4 \times 9$

$= 36$

Now check if $36$ is a perfect square:

$36 = 6^2$ ✔

So, the smallest perfect square divisible by all three numbers is 36.

Correct Answer: 36