Manoj travels from City A to City B.
Manoj travels from City A to City B. If Manoj drives his car at \(\frac{1}{5}\) of his normal speed. then he reaches City B 36 minutes late. Find the time (in minutes) that Manoj would have taken to travel from City A to City B if he drove at his normal speed.
मनोज शहर A से शहर B तक यात्रा करता है। यदि मनोज अपनी कार को अपनी सामान्य चाल की \(\frac{1}{5}\) चाल पर चलाता है, तो वह शहर B तक 36 मिनट देरी से पहुंचता है। यदि मनोज अपनी कार सामान्य चाल से चलता, तो शहर A से शहर B तक यात्रा करने में उसे कितना समय (मिनट में) लगता?
Detailed Solution & Logic
9
Let normal speed time = t minutes
At $ \frac{1}{5} $ of normal speed, time becomes 5t
Given delay = 36 minutes
5t - t = 36
4t = 36
t = 9
Answer: 9 minutes
Similar Practice Questions
A car travels from A to B at 80 km/ h and returns at 60 km/h. Find the approx. average speed of the car.
A car travels from A to B at 80 km/ h and returns at 60...
Rachin travels a distance at 60 km/hr for 2 hours
Rachin travels a distance at 60 km/hr for 2 hours and 80 km at 40...
The average speed of a car running at 70 km/hr for 1 hour and ‘P’ km/hr for $1\frac{1}{2}$ hour is 55km/hr. Find the value of p
The average speed of a car running at 70 km/hr for 1 hour and ‘P’...
In a circular race of 1500 m, P and Q start
In a circular race of 1500 m, P and Q start from the same point...
Ravi goes to college from his village
Ravi goes to college from his village at the speed of 5km/h and returns at...
A thief saw a policeman, and he started running
A thief saw a policeman, and he started running at a speed of 18 m/s....
A 725 m long train passes through a 235
A 725 m long train passes through a 235 m long tunnel in 48 sec....