Find the value of \(79 – 10\times [2 +3\times \{12 – 6 (6 – 5)\times 2\} \div 20]\)
Find the value of \(79 – 10\times [2 +3\times \{12 – 6 (6 – 5)\times 2\} \div 20]\)
\(79 – 10\times [2 +3\times \{12 – 6 (6 – 5)\times 2\} \div 20]\) का मान ज्ञात कीजिए।
Detailed Solution & Logic
Correct Answer:
59
= \(79 - 10 \times [2 + 3 \times {12 - 6(6-5)\times 2} \div 20]\)
= \(79 - 10 \times [2 + 3 \times {12 - 6 \times 1 \times 2} \div 20]\)
= \(79 - 10 \times [2 + 3 \times {12 - 12} \div 20]\)
= \(79 - 10 \times [2 + 3 \times 0\div 20]\)
= \(79 - 10 \times [2 + 0]\)
= \(79 - 10 \times 2\)
= 79 - 20
= 59
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