Find the value of

$ [(48\div 8)\times\{\frac {49}{7} + \frac {40}{4}\times (7 - 3)\}] $
$[(48\div 8)\times{\frac{49}{7} + \frac{40}{4}\times (7 - 3)}] $
= $[6 \times {7 + 10 \times 4}] $
= $[6 \times (7 + 40)] $
= $ 6 \times 47 $
Answer = 282