If an angle is \(10^\circ\) more than twice its complement, what is the angle?
If an angle is \(10^\circ\) more than twice its complement, what is the angle?
अगर कोई कोण अपने पूरक कोण के दौगुने से \(10^\circ\) अधिक है, तो वह कोण क्या हैं?
Detailed Solution & Logic
Correct Answer:
\(63.33^\circ\)
$ x=2(90-x)+10 $
$ x=180-2x+10 $
$ x=190-2x $
$ 3x=190 $
$ x=\dfrac{190}{3}^\circ $
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