If sec A + tan A = P, then what is sec A in terms of P?
If sec A + tan A = P, then what is sec A in terms of P?
यदि secA + tanA =P, तो p के संदर्भ में secA क्या है?
Detailed Solution & Logic
Correct Answer:
$\frac{{P}^2 +1}{2p}$
दी गई जानकारी:
$ \sec A + \tan A = P $
Step 1:
हम जानते हैं:
$ (\sec A + \tan A)(\sec A - \tan A) = 1 $
तो,
$ \sec A - \tan A = \frac{1}{P} $
Step 2: दोनों समीकरण जोड़ें:
$ (\sec A + \tan A) + (\sec A - \tan A) = P + \frac{1}{P} $
$ 2\sec A = P + \frac{1}{P} $
Step 3:
$ \sec A = \frac{1}{2}\left(P + \frac{1}{P}\right) $
इसे सरल करें:
$ \sec A = \frac{P^2 + 1}{2P} $
सही उत्तर:
$ \frac{P^2 + 1}{2p} $ ✅
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