We are asked to simplify:
$(\sqrt{7})^6 \div (\sqrt{7})^4 = 7^n$
Step 1: Write square roots as exponents
$\sqrt{7} = 7^{1/2}$
So:
$(\sqrt{7})^6 = (7^{1/2})^6 = 7^{6/2} = 7^3$
$(\sqrt{7})^4 = (7^{1/2})^4 = 7^{4/2} = 7^2$
Step 2: Divide using exponent rule
$7^3 \div 7^2 = 7^{3-2} = 7^1$
Answer: n = 1