Simplify \({\sqrt[3]{0.216}} +{\sqrt[3]{0.001}} -{\sqrt[3] {0.008}}\)

We need to solve:

$\sqrt[3]{0.216}+\sqrt[3]{0.001}-\sqrt[3]{0.008}$

Find cube roots:

$\sqrt[3]{0.216}=0.6$

because $0.6^3=0.216$

$\sqrt[3]{0.001}=0.1$

because $0.1^3=0.001$

$\sqrt[3]{0.008}=0.2$

because $0.2^3=0.008$

Now substitute: 0.6+0.1-0.2

=0.5

Final Answer: 0.5