$10\frac{2}{3}+3\frac{1}{6} -5\frac{5}{6} – 2\frac{1}{3}=? $

Given:

$10\frac{2}{3}+3\frac{1}{6}-5\frac{5}{6}-2\frac{1}{3}$

Convert mixed fractions into improper fractions:

$10\frac{2}{3}=\frac{32}{3}$

$3\frac{1}{6}=\frac{19}{6}$

$5\frac{5}{6}=\frac{35}{6}$

$2\frac{1}{3}=\frac{7}{3}$

Now take LCM = 6:

$\frac{64}{6}+\frac{19}{6}-\frac{35}{6}-\frac{14}{6}$

$=\frac{83-49}{6}$

$=\frac{34}{6}$

$=\frac{17}{3}$

$=5\frac{2}{3}$

✅ Correct answer: $5\frac{2}{3}$