A farmer’s land is two adjoining trapezoids: T1 with bases 70m & 50m, height 20m;  T2 with bases 50m & 30m, height 15 m. Land costs ₹60/ $m^2$. What is the total land cost?

Given:
T₁: Bases = 70 m, 50 m; Height = 20 m
T₂: Bases = 50 m, 30 m; Height = 15 m
Cost = ₹60 per m²
Area of T₁
$= \frac{1}{2} (70 + 50) \times 20$
$= \frac{1}{2} \times 120 \times 20$
$= 60 \times 20$
$= 1200 , m^2$
Area of T₂
$= \frac{1}{2} (50 + 30) \times 15$
$= \frac{1}{2} \times 80 \times 15$
$= 40 \times 15$
$= 600 , m^2$
Total Area
$= 1200 + 600 = 1800 , m^2$
Total Cost
$= 1800 \times 60 = 108000$

Final Answer: ₹1,08,000 / 108000 रुपये ✅