What smallest number should be added to 16809 so that the sum is completely divisible by 41?
What smallest number should be added to 16809 so that the sum is completely divisible by 41?
वह सबसे छोटी संख्या ज्ञात कीजिए, जिसे 16809 में जोड़ने पर प्राप्त योगफल 41 से पूर्णतः विभाज्य हो जाए।
Detailed Solution & Logic
Correct Answer:
1
We need the smallest number to add to 16809 so that the result is divisible by 41.
First find the remainder when 16809 is divided by 41:
$41 \times 410 = 16810$
So, $16809$ is $1$ less than $16810$.
Hence, remainder = $40$ (or equivalently, $-1$ modulo 41).
To make it divisible, we need to add:
$41 - 40 = 1$
Correct Answer: 1
Similar Practice Questions
The sum of five consecutive numbers is 80. Find the largest number.
The sum of five consecutive numbers is 80. Find the largest number. पाँच क्रमागत संख्याओं...
Evaluate :
Evaluate / हल कीजिए : \(2\times\{17 – 2 \times (11 – 4)\}\)
Which of the following can be the value of ‘k’
Which of the following can be the value of ‘k’ so that the number 217924k...
20% of a number is more than 20% of 620 by 210. The number is:
20% of a number is more than 20% of 620 by 210. The number is:...
Find the value of \(\sqrt{{385}+\sqrt{{213} +\sqrt{{144}}}}\)
Find the value of / मान ज्ञात कीजिए। \(\sqrt{{385}+\sqrt{{213} +\sqrt{{144}}}}\)
The least multiple of 11, which leaves a remainder of 8,
The least multiple of 11, which leaves a remainder of 8, when divided by 5,...
What is the difference between the largest and the smallest four-digit number that starts with 3 and ends with 5?
What is the difference between the largest and the smallest four-digit number that starts with...