\(\frac{(2.3)^3 + 0.027}{(2.3)^2 – 0.69 +0.09}\) बराबर हैं?

Evaluate:

$\frac{(2.3)^3 + 0.027}{(2.3)^2 - 0.69 + 0.09}$

Notice:
$0.027 = (0.3)^3$ and $0.09 = (0.3)^2$

So expression becomes:
$\frac{(2.3)^3 + (0.3)^3}{(2.3)^2 - (2.3)(0.3) + (0.3)^2}$

Use identity:
$\frac{a^3 + b^3}{a^2 - ab + b^2} = a + b$

Here $a = 2.3$, $b = 0.3$

So value =
$2.3 + 0.3 = 2.6$

✅ Final Answer: 2.6