A banner is shaped like a trapezium with bases 5 m and 3 m, and height 4m. If printing costs ₹$ 250/m^2$, what is the total cost?
A banner is shaped like a trapezium with bases 5 m and 3 m, and height 4m. If printing costs ₹$ 250/m^2$, what is the total cost?
एक बैनर समलम्ब चतुर्भुज के आकार का है जिसका आधार 5 मीटर और 3 मीटर है, तथा ऊँचाई 4 मीटर हैं। यदि छिपाई की लागत ₹250/ वर्ग मीटर है, तो कुल लागत क्या हैं?
Detailed Solution & Logic
₹4, 000
Given:
Bases of trapezium = 5 m and 3 m
Height = 4 m
Printing cost = ₹250 per m²
Area of trapezium
$= \frac{1}{2} \times (sum\ of\ parallel\ sides) \times height$
$= \frac{1}{2} \times (5 + 3) \times 4$
$= \frac{1}{2} \times 8 \times 4$
$= 4 \times 4$
$= 16 , m^2$
Total printing cost
$= Area \times Cost\ per\ m^2$
$= 16 \times 250$
$= 4000$
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